WebApr 12, 2024 · Solution For side of the triangle is extended, the external angle formed on the extended side is to the sum,of the two internally opposite angles. Ex. The world’s only live instant tutoring platform. Become a tutor About us Student login Tutor login. Login. Student Tutor. Filo instant Ask button for chrome browser. ... WebMar 29, 2024 · Question 14 If S is a point on side PQ of a ∆ PQR such that PS = QS = RS, then PR . QR = RS2 (B) QS2 + RS2 = QR2 (C) PR2 + QR2 = PQ2 (D) PS2 + RS2 = PR2 Given PS = QS = RS Now, We know that Angles opposite equal sides are equal In Δ …
Pqr is a Triangle. S is a Point on the Side Qr Of δPqr Such That …
WebGiven: Q is point on side SR in DPSR and PQ = PR. To Prove = PS > PQ. Proof: We know that exterior angle of any triangle is greater than each of the opposite interior angles. PQR is … WebPS = QS or PS = SR so, PQS and PSR is an isosceles triangle. In triangle PSR ∠SRP = ∠SPR 24° = ∠SPR (Angle opposite to equal sides of a triangle are equal). ∠SPR + ∠SRP + ∠PSR = 180° ⇒ 24° + 24° + ∠PSR = 180° ⇒ 48° + ∠PSR = 180° ⇒ ∠PSR = 180° - 48° ⇒ ∠PSR = 132° ---- (3) Similarly, In triangle PQS ∠SQP = ∠SPQ In triangle PQS granite countertops kannapolis nc
In figure, PQ = PR, show that PS > PQ - Sarthaks
WebApr 7, 2024 · Question asked by Filo student. (3) Theree point charges, +Q,+2Q and −3Q are placed at the vertices of an equilateral triang ABC of side l. If these charges are displaced to the midpoints A1,B1 and C 1 respectively, Fin the amount of workclone in St the charges to new location [−4Ωε01⋅l7Q2] Viewed by: 5,518 students. Updated on: Apr 7 ... WebMar 3, 2024 · In triangle PQR, the angle Q = 90 degree, PQ = 6 cm, QR = 8 cm. X is a variable point on PQ. The line through X parallel to QR, intersects PR at Y and the line through Y, parallel to PQ, intersects QR at Z. Find the least possible length of XZ. A. 3.6 cm. B. 2.4 cm. C. 4.8 cm. D. 2.16 cm. E. 3.2 cm. Show Answer. WebJun 14, 2024 · In figure, PQ = PR, show that PS > PQ triangles class-9 1 Answer 0 votes answered Jun 14, 2024 by faiz (316k points) selected Jun 14, 2024 by Golu Best answer In ∆PQR ∴ PQ = PR ⇒ ∠PRQ = ∠PQR .... (i) [Angles opposite to equal sides] In ∆PSQ, SQ is produced to R ∴ Ext. ∠PQR > ∠PSQ .... (ii) ∠PRQ > ∠PSQ [By eq. (i) and (ii)] ⇒ ∠PRS > ∠PSR chinle treatment center